Optimal. Leaf size=138 \[ -\frac{a^2 \cos (c+d x)}{d}+\frac{4 a b x \sin (c+d x)}{d^2}+\frac{4 a b \cos (c+d x)}{d^3}-\frac{2 a b x^2 \cos (c+d x)}{d}+\frac{4 b^2 x^3 \sin (c+d x)}{d^2}+\frac{12 b^2 x^2 \cos (c+d x)}{d^3}-\frac{24 b^2 x \sin (c+d x)}{d^4}-\frac{24 b^2 \cos (c+d x)}{d^5}-\frac{b^2 x^4 \cos (c+d x)}{d} \]
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Rubi [A] time = 0.163132, antiderivative size = 138, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 3, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.188, Rules used = {3329, 2638, 3296} \[ -\frac{a^2 \cos (c+d x)}{d}+\frac{4 a b x \sin (c+d x)}{d^2}+\frac{4 a b \cos (c+d x)}{d^3}-\frac{2 a b x^2 \cos (c+d x)}{d}+\frac{4 b^2 x^3 \sin (c+d x)}{d^2}+\frac{12 b^2 x^2 \cos (c+d x)}{d^3}-\frac{24 b^2 x \sin (c+d x)}{d^4}-\frac{24 b^2 \cos (c+d x)}{d^5}-\frac{b^2 x^4 \cos (c+d x)}{d} \]
Antiderivative was successfully verified.
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Rule 3329
Rule 2638
Rule 3296
Rubi steps
\begin{align*} \int \left (a+b x^2\right )^2 \sin (c+d x) \, dx &=\int \left (a^2 \sin (c+d x)+2 a b x^2 \sin (c+d x)+b^2 x^4 \sin (c+d x)\right ) \, dx\\ &=a^2 \int \sin (c+d x) \, dx+(2 a b) \int x^2 \sin (c+d x) \, dx+b^2 \int x^4 \sin (c+d x) \, dx\\ &=-\frac{a^2 \cos (c+d x)}{d}-\frac{2 a b x^2 \cos (c+d x)}{d}-\frac{b^2 x^4 \cos (c+d x)}{d}+\frac{(4 a b) \int x \cos (c+d x) \, dx}{d}+\frac{\left (4 b^2\right ) \int x^3 \cos (c+d x) \, dx}{d}\\ &=-\frac{a^2 \cos (c+d x)}{d}-\frac{2 a b x^2 \cos (c+d x)}{d}-\frac{b^2 x^4 \cos (c+d x)}{d}+\frac{4 a b x \sin (c+d x)}{d^2}+\frac{4 b^2 x^3 \sin (c+d x)}{d^2}-\frac{(4 a b) \int \sin (c+d x) \, dx}{d^2}-\frac{\left (12 b^2\right ) \int x^2 \sin (c+d x) \, dx}{d^2}\\ &=\frac{4 a b \cos (c+d x)}{d^3}-\frac{a^2 \cos (c+d x)}{d}+\frac{12 b^2 x^2 \cos (c+d x)}{d^3}-\frac{2 a b x^2 \cos (c+d x)}{d}-\frac{b^2 x^4 \cos (c+d x)}{d}+\frac{4 a b x \sin (c+d x)}{d^2}+\frac{4 b^2 x^3 \sin (c+d x)}{d^2}-\frac{\left (24 b^2\right ) \int x \cos (c+d x) \, dx}{d^3}\\ &=\frac{4 a b \cos (c+d x)}{d^3}-\frac{a^2 \cos (c+d x)}{d}+\frac{12 b^2 x^2 \cos (c+d x)}{d^3}-\frac{2 a b x^2 \cos (c+d x)}{d}-\frac{b^2 x^4 \cos (c+d x)}{d}-\frac{24 b^2 x \sin (c+d x)}{d^4}+\frac{4 a b x \sin (c+d x)}{d^2}+\frac{4 b^2 x^3 \sin (c+d x)}{d^2}+\frac{\left (24 b^2\right ) \int \sin (c+d x) \, dx}{d^4}\\ &=-\frac{24 b^2 \cos (c+d x)}{d^5}+\frac{4 a b \cos (c+d x)}{d^3}-\frac{a^2 \cos (c+d x)}{d}+\frac{12 b^2 x^2 \cos (c+d x)}{d^3}-\frac{2 a b x^2 \cos (c+d x)}{d}-\frac{b^2 x^4 \cos (c+d x)}{d}-\frac{24 b^2 x \sin (c+d x)}{d^4}+\frac{4 a b x \sin (c+d x)}{d^2}+\frac{4 b^2 x^3 \sin (c+d x)}{d^2}\\ \end{align*}
Mathematica [A] time = 0.19794, size = 86, normalized size = 0.62 \[ \frac{4 b d x \left (a d^2+b \left (d^2 x^2-6\right )\right ) \sin (c+d x)-\left (a^2 d^4+2 a b d^2 \left (d^2 x^2-2\right )+b^2 \left (d^4 x^4-12 d^2 x^2+24\right )\right ) \cos (c+d x)}{d^5} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.007, size = 336, normalized size = 2.4 \begin{align*}{\frac{1}{d} \left ({\frac{{b}^{2} \left ( - \left ( dx+c \right ) ^{4}\cos \left ( dx+c \right ) +4\, \left ( dx+c \right ) ^{3}\sin \left ( dx+c \right ) +12\, \left ( dx+c \right ) ^{2}\cos \left ( dx+c \right ) -24\,\cos \left ( dx+c \right ) -24\, \left ( dx+c \right ) \sin \left ( dx+c \right ) \right ) }{{d}^{4}}}-4\,{\frac{{b}^{2}c \left ( - \left ( dx+c \right ) ^{3}\cos \left ( dx+c \right ) +3\, \left ( dx+c \right ) ^{2}\sin \left ( dx+c \right ) -6\,\sin \left ( dx+c \right ) +6\, \left ( dx+c \right ) \cos \left ( dx+c \right ) \right ) }{{d}^{4}}}+2\,{\frac{ab \left ( - \left ( dx+c \right ) ^{2}\cos \left ( dx+c \right ) +2\,\cos \left ( dx+c \right ) +2\, \left ( dx+c \right ) \sin \left ( dx+c \right ) \right ) }{{d}^{2}}}+6\,{\frac{{b}^{2}{c}^{2} \left ( - \left ( dx+c \right ) ^{2}\cos \left ( dx+c \right ) +2\,\cos \left ( dx+c \right ) +2\, \left ( dx+c \right ) \sin \left ( dx+c \right ) \right ) }{{d}^{4}}}-4\,{\frac{abc \left ( \sin \left ( dx+c \right ) - \left ( dx+c \right ) \cos \left ( dx+c \right ) \right ) }{{d}^{2}}}-4\,{\frac{{b}^{2}{c}^{3} \left ( \sin \left ( dx+c \right ) - \left ( dx+c \right ) \cos \left ( dx+c \right ) \right ) }{{d}^{4}}}-{a}^{2}\cos \left ( dx+c \right ) -2\,{\frac{ab{c}^{2}\cos \left ( dx+c \right ) }{{d}^{2}}}-{\frac{{b}^{2}{c}^{4}\cos \left ( dx+c \right ) }{{d}^{4}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.05426, size = 394, normalized size = 2.86 \begin{align*} -\frac{a^{2} \cos \left (d x + c\right ) + \frac{b^{2} c^{4} \cos \left (d x + c\right )}{d^{4}} + \frac{2 \, a b c^{2} \cos \left (d x + c\right )}{d^{2}} - \frac{4 \,{\left ({\left (d x + c\right )} \cos \left (d x + c\right ) - \sin \left (d x + c\right )\right )} b^{2} c^{3}}{d^{4}} - \frac{4 \,{\left ({\left (d x + c\right )} \cos \left (d x + c\right ) - \sin \left (d x + c\right )\right )} a b c}{d^{2}} + \frac{6 \,{\left ({\left ({\left (d x + c\right )}^{2} - 2\right )} \cos \left (d x + c\right ) - 2 \,{\left (d x + c\right )} \sin \left (d x + c\right )\right )} b^{2} c^{2}}{d^{4}} + \frac{2 \,{\left ({\left ({\left (d x + c\right )}^{2} - 2\right )} \cos \left (d x + c\right ) - 2 \,{\left (d x + c\right )} \sin \left (d x + c\right )\right )} a b}{d^{2}} - \frac{4 \,{\left ({\left ({\left (d x + c\right )}^{3} - 6 \, d x - 6 \, c\right )} \cos \left (d x + c\right ) - 3 \,{\left ({\left (d x + c\right )}^{2} - 2\right )} \sin \left (d x + c\right )\right )} b^{2} c}{d^{4}} + \frac{{\left ({\left ({\left (d x + c\right )}^{4} - 12 \,{\left (d x + c\right )}^{2} + 24\right )} \cos \left (d x + c\right ) - 4 \,{\left ({\left (d x + c\right )}^{3} - 6 \, d x - 6 \, c\right )} \sin \left (d x + c\right )\right )} b^{2}}{d^{4}}}{d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.77237, size = 204, normalized size = 1.48 \begin{align*} -\frac{{\left (b^{2} d^{4} x^{4} + a^{2} d^{4} - 4 \, a b d^{2} + 2 \,{\left (a b d^{4} - 6 \, b^{2} d^{2}\right )} x^{2} + 24 \, b^{2}\right )} \cos \left (d x + c\right ) - 4 \,{\left (b^{2} d^{3} x^{3} +{\left (a b d^{3} - 6 \, b^{2} d\right )} x\right )} \sin \left (d x + c\right )}{d^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 3.03674, size = 172, normalized size = 1.25 \begin{align*} \begin{cases} - \frac{a^{2} \cos{\left (c + d x \right )}}{d} - \frac{2 a b x^{2} \cos{\left (c + d x \right )}}{d} + \frac{4 a b x \sin{\left (c + d x \right )}}{d^{2}} + \frac{4 a b \cos{\left (c + d x \right )}}{d^{3}} - \frac{b^{2} x^{4} \cos{\left (c + d x \right )}}{d} + \frac{4 b^{2} x^{3} \sin{\left (c + d x \right )}}{d^{2}} + \frac{12 b^{2} x^{2} \cos{\left (c + d x \right )}}{d^{3}} - \frac{24 b^{2} x \sin{\left (c + d x \right )}}{d^{4}} - \frac{24 b^{2} \cos{\left (c + d x \right )}}{d^{5}} & \text{for}\: d \neq 0 \\\left (a^{2} x + \frac{2 a b x^{3}}{3} + \frac{b^{2} x^{5}}{5}\right ) \sin{\left (c \right )} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.10529, size = 134, normalized size = 0.97 \begin{align*} -\frac{{\left (b^{2} d^{4} x^{4} + 2 \, a b d^{4} x^{2} + a^{2} d^{4} - 12 \, b^{2} d^{2} x^{2} - 4 \, a b d^{2} + 24 \, b^{2}\right )} \cos \left (d x + c\right )}{d^{5}} + \frac{4 \,{\left (b^{2} d^{3} x^{3} + a b d^{3} x - 6 \, b^{2} d x\right )} \sin \left (d x + c\right )}{d^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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